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11x^2-24x-275=0
a = 11; b = -24; c = -275;
Δ = b2-4ac
Δ = -242-4·11·(-275)
Δ = 12676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12676}=\sqrt{4*3169}=\sqrt{4}*\sqrt{3169}=2\sqrt{3169}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-2\sqrt{3169}}{2*11}=\frac{24-2\sqrt{3169}}{22} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+2\sqrt{3169}}{2*11}=\frac{24+2\sqrt{3169}}{22} $
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